Trouble with Integer vs. String Variables

[bobmaucher]

Hi,

I'm trying to make a macro that looks for an image on the screen, and when it sees the image, it left-clicks it.

Here is my code:

1 | IF | DETECT IMAGE | image path C:\Users\bobma\Desktop\RipeSunflower.png::match quick::move mouse no::save to vars X Y | IMAGE FOUND | CONTINUE

 2 | RUN ACTION | MOUSE CLICK | Left click at %X% %Y%

 3 | RUN ACTION | WAIT SECONDS | 1

 4 | RUN ACTION | MOUSE CLICK | Left click at %X% %Y%

5 | IF | END IF

6 | RUN ACTION | WAIT SECONDS | 1
I'm getting this error:

Playback error:  2 | RUN ACTION | MOUSE CLICK | Left click at %X% %Y% - Condition execution error Conversion from string "%x%" to type 'Integer' is not valid.

I can't figure out how to make sure the X and Y variables are defined as integers - it seems the program is setting them as strings, and then tries to interpret the strings as integers when it's getting direction where to click.  What am I doing wrong?

Thank you

[philranger]

Hello,

  I know that mmm is quite strict about spacing, I never tried to put spaces at the beginning of lines and can't check now, but worth a try.  Also, my clicks are never "run actions" .

Maybe something more like this?


2 | %INTEGER1% | %INTEGER2% | 100 | Left Click

Regards

[Steve]

Aug 27, 2021 16:08:48 GMT bobmaucher said:

Playback error:  2 | RUN ACTION | MOUSE CLICK | Left click at %X% %Y% - Condition execution error Conversion from string "%x%" to type 'Integer' is not valid.

I can't figure out how to make sure the X and Y variables are defined as integers - it seems the program is setting them as strings, and then tries to interpret the strings as integers when it's getting direction where to click.  What am I doing wrong?

Thank you

This was an error with version 8.3.1.0. It was patched a couple of weeks ago. Update to the latest version.

[bobmaucher]

Upgrading was my problem - thank you!

[mrclicker]

i had a similar issue where, after the upgrade to 8.3.2.1, previously made macros where variable were defined as integers failed in an IF statement when comapring them to another integer i got an error saying it is a string and not an integer