Post by freddy on Aug 21, 2021 20:16:45 GMT
I am trying to use the Run Program command line? or condition to open my Express Vpn app and connect to a server location.
I can make a mouse macro that clicks on the express vpn app and then selects the server location but I think using the Run Program condition to do this instead would be better.
If I use the code below that opens the express vpn app only.
1 | RUN ACTION | RUN PROGRAM | C:\Program Files (x86)\ExpressVPN\expressvpn-ui\ExpressVPN.exe
I also tried to use the arguments portion below to make the vpn open the Ukraine server location but that did not work either.
1 | RUN ACTION | RUN PROGRAM | C:\Program Files (x86)\ExpressVPN\expressvpn-ui\ExpressVPN.exe::"ukraine" /e
What am I doing wrong?
I can make a mouse macro that clicks on the express vpn app and then selects the server location but I think using the Run Program condition to do this instead would be better.
If I use the code below that opens the express vpn app only.
1 | RUN ACTION | RUN PROGRAM | C:\Program Files (x86)\ExpressVPN\expressvpn-ui\ExpressVPN.exe
I also tried to use the arguments portion below to make the vpn open the Ukraine server location but that did not work either.
1 | RUN ACTION | RUN PROGRAM | C:\Program Files (x86)\ExpressVPN\expressvpn-ui\ExpressVPN.exe::"ukraine" /e
What am I doing wrong?